Question
Question: In what ratio is a line segment joining the points (-2,-3) and (3,7) divided by \(y\)-axis? \( ...
In what ratio is a line segment joining the points (-2,-3) and (3,7) divided by y-axis?
A. 32 B. 23 C. 54 D. 45
Solution
In this problem first we let the ratio in which y-axis divides the given line segment be in m:n.Then we apply the Section Formula on coordinates of that point to get relation between m and n.And finally we put x−coordinate of point obtained from Section Formula to get ratio of m and n.
Complete step by step answer:
Let y-axis divide the line segment joining the point (-2,-3) and (3,7) in the m:nratio internally.
Since, the line segment is divided by y-axis sox coordinate of the point is 0. Let the coordinates of the point which divides the line segment be ( 0,y)
Section Formula: If a point divides a line segment in m:n whose endpoints coordinates are (x1,y1) and (x2,y2) then the coordinates of that point are
⇒(m+nmx2+nx1,m+nmy2+ny1)
Using Section Formula the coordinates of the point of division of line segment whose endpoints
(-2,-3) and (3,7) in m:nratio.
\Rightarrow \left( {\dfrac{{m(3) + n( - 2)}}{{m + n}},\dfrac{{m(7) + n( - 3)}}{{m + n}}} \right) \\\
\Rightarrow \left( {\dfrac{{3m - 2n}}{{m + n}},\dfrac{{7m - 3n}}{{m + n}}} \right){\text{ }} \\\
eq.1
Since we let the coordinates of division points be (0,y).
Then,
⇒(m+n3m−2n,m+n7m−3n)=(0,y)
On comparing x coordinate of above equation we get
⇒m+n3m−2n=0 ⇒3m−2n=0 ⇒3m=2n ⇒nm=32
Therefore, the ratio in which y axis divides the given line segment is 2:3.
Hence, option A. is correct
Note:
Whenever you get this type of problem the key concept of solving is to have knowledge about
how a given point divides the line segment like in this question dividing point lies on y axis so its coordinates must be in form ( 0 ,y) . And using Section Formula (m+nmx2+nx1,m+nmy2+ny1) you can find the required result.