Solveeit Logo

Question

Question: In what ratio is a line segment joining the points (-2,-3) and (3,7) divided by y axis? \( {\t...

In what ratio is a line segment joining the points (-2,-3) and (3,7) divided by y axis?
A. 23  B. 32  C. 45  D. 54   {\text{A}}{\text{. }}\dfrac{2}{3}{\text{ }} \\\ {\text{B}}{\text{. }}\dfrac{3}{2}{\text{ }} \\\ {\text{C}}{\text{. }}\dfrac{4}{5}{\text{ }} \\\ {\text{D}}{\text{. }}\dfrac{5}{4}{\text{ }} \\\

Explanation

Solution

Hint:In this problem first we let the ratio in which yyaxis divides the given line segment be in m:nm:n. Then we apply the Section Formula on coordinates of that point to get a relation between m and nm{\text{ and }}n. And finally we put xx coordinate of points obtained from Section Formula to get a ratio of m and nm{\text{ and }}n.

Complete step-by-step answer:
Let y axis divide the line segment joining the point (-2,-3) and (3,7) in m:n ratio internally.
Since, the line segment is divided by y axis soxx coordinate of the point is 0. Let the coordinates of the point which divides the line segment be (0,y) .
Section Formula: If a point divides a line segment in m:nm:n whose endpoints coordinates are (x1,y1) and (x2,y2)({x_1},{y_1}){\text{ and }}({x_2},{y_2}) then the coordinates of that point are
\Rightarrow \left( {\dfrac{{m{x_2} + n{x_1}}}{{m + n}},\dfrac{{m{y_2} + n{y_1}}}{{m + n}}} \right) \\\
Using Section Formula the coordinates of the point of division of the line segment whose endpoints (-2,-3) and (3,7) in m:n ratio.
(m(3)+n(2)m+n,m(7)+n(3)m+n) (3m2nm+n,7m3nm+n) eq.1  \Rightarrow \left( {\dfrac{{m(3) + n( - 2)}}{{m + n}},\dfrac{{m(7) + n( - 3)}}{{m + n}}} \right) \\\ \Rightarrow \left( {\dfrac{{3m - 2n}}{{m + n}},\dfrac{{7m - 3n}}{{m + n}}} \right){\text{ eq}}{\text{.1}} \\\
Since we let the coordinates of division points be (0,y) .
Then,
\Rightarrow \left( {\dfrac{{3m - 2n}}{{m + n}},\dfrac{{7m - 3n}}{{m + n}}} \right) = (0,y) \\\
On comparing xx - coordinate of above equation we get
\Rightarrow \dfrac{{3m - 2n}}{{m + n}} = 0 \\\ \Rightarrow 3m - 2n = 0 \\\ \Rightarrow 3m = 2n \\\ \Rightarrow \dfrac{m}{n} = \dfrac{2}{3} \\\

Therefore, the ratio in which yy-axis divides the given line segment is 2:32:3.
Hence, option A. is correct

Note:Whenever you get this type of problem the key concept of solving is to have knowledge about
how a given point divides the line segment like in this question dividing point lies on y axis so its coordinates must be in the form(0,y)(0,y). And using Section Formula (mx2+nx1m+n,my2+ny1m+n)\left( {\dfrac{{m{x_2} + n{x_1}}}{{m + n}},\dfrac{{m{y_2} + n{y_1}}}{{m + n}}} \right) you can find the required result.