Question
Question: In vinyl acetylene \(CH \equiv C - CH = C{H_2}\) type of overlapping in \(\left( {{C_2}\sigma {C_3}}...
In vinyl acetylene CH≡C−CH=CH2 type of overlapping in (C2σC3) bond is
A.sp2−sp
B.sp−sp2
C.sp3−sp3
D.sp3−sp2
Solution
We have to take into consideration the number of bonds formed by each carbon and determine whether the bonds are σ−bonds (or) π−bonds. We can determine the hybridization of each atom of carbon using the σ−bonds (or) π−bonds.
Complete step by step answer:
We have to first identify the name of atoms of carbon. We can give the structure as,
1CH≡2C−3CH=4CH2
We have to find the hybridization of two carbons present in the middle. Let us carbon-2.
From the written structure, we could see that it is forming one σ−bond and two π−bonds with carbon-3. We can also see it does not form any bonds with hydrogen atoms.
Therefore, it contains two σ−bonds. We have to consider the bond pairs while determining the hybridization of the atoms. We should not consider the π−bonds while determining the hybridization of the atom.
We can say that there are two bond pairs involved, and therefore, 2 hybridized orbitals are needed to accommodate them. Hence, the hybridization of this carbon atom will be sp.
Let us now consider carbon-3.
From the structure, we could see that one σ−bond and two π−bonds with carbon-2. We can also see it forms one σ−bond with a hydrogen atom.
Let us consider the number of σ−bond to calculate the hybridization of the carbon. There are 3 σ−bonds present and 3 hybridized orbitals are needed to accommodate 3 bond pairs. Therefore, the hybridization of the carbon atom will be sp2.
Therefore, the option (B) is correct.
Note: We have to be careful while calculating the number of σ−bond which is formed by each of the carbon and the hydrogen atom since they are not explicitly shown and there is a chance one might miss them. We can prepare vinyl acetylene by Hofmann elimination of the quaternary ammonium salt. We can also prepare using dehydrohalogenation of 1,3-dichloro-2-butene.