Question

In two circuit shown above the value of current I1 (in amperes) is equal to $-\frac{y}{5}A$ . Value of y is equal to

Answer 1

The correct answer is 11.
Using Kirchoff’s law.
I1 + I3 – I2 = –2 …(i)
I3 + 2I2 = 5 …(ii)
2I2 – (I3 – I2) – (I1 + I3 – I2) = 5 …(iii)
$⇒$ l1 $=-\frac{11}{5}A$
$⇒$ y = 11