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Question

Mathematics Question on Trigonometric Functions

In triangle ABC. if a = 3 ,b = 4,c = 6, then cot⁡A2+cot⁡B2+cot⁡C2cot⁡A+cot⁡B+cotC=\frac{\cot \frac{A}{2} + \cot \frac{B}{2} + \cot \frac{C}{2}}{\cot A +\cot B + cot C} =

A

1361\frac{13}{61}

B

16961\frac{169}{61}

C

61169\frac{61}{169}

D

6113\frac{61}{13}

Answer

16961\frac{169}{61}

Explanation

Solution

Answer (b) 16961\frac{169}{61}