Question

In this sequence of reaction A, B, C and D are respectively:

(A) $\left[ {{\left( RC{{H}_{2}}C{{H}_{2}} \right)}_{3}}B \right],\left[ RC{{H}_{2}}C{{H}_{2}}OH \right],\left[ RC{{H}_{2}}C{{H}_{3}} \right],\left[ HI \right]$
(B) $\left[ {{\left( RC{{H}_{2}}C{{H}_{2}} \right)}_{3}}B \right],\left[ RCH(OH)C{{H}_{3}} \right],\left[ RC{{H}_{2}}C{{H}_{3}} \right],\left[ HI \right]$
(C) $\left[ {{\left( RC{{H}_{2}}C{{H}_{2}} \right)}_{3}}B \right],\left[ RCH(OH)C{{H}_{2}}C{{H}_{3}} \right],\left[ RC{{H}_{2}}C{{H}_{3}} \right],\left[ HI \right]$
(D) None of the above.

Answer 1

Hint : We know that alcohol is derivatives of hydrocarbons whose functional group is $-OH$ as $-OH$ has replaced a hydrogen atom. Depending on the presence of hydroxyl groups in the compound there are different types of alcohol i.e. primary alcohol, secondary alcohol, and tertiary alcohol.

Complete Step By Step Answer:
When hydroxyl group atoms form a bond with saturated carbon atoms, alcohol is formed. Now, if the dehydration of alcohol takes place, then we get ether. In this chapter, you will get to learn how these compounds are connected to one another. In addition to this, there are three types of alcohols: Monohydric, Dihydric, and Trihydric alcohols. All three are classified on the basis of their hydroxyl groups. Monohydric, Dihydric, and Trihydric alcohols contain one $-OH$ group, two $-OH$ groups, and three groups, respectively. Moreover, the other three types of alcohol are primary, secondary, and tertiary alcohols. This reaction takes place in the presence of protic acid i.e. sulphuric acid alcohol undergoes dehydration to produce alkenes and ether as their minor and major products. This reaction occurs. This is the ideal method of preparation of ether.
The reaction of $RCH=C{{H}_{2}}$ ​ with $B{{H}_{3}}THF$ ​ followed by oxidation with alkaline ${{H}_{2}}{{O}_{2}}$ ​ gives $RC{{H}_{2}}C{{H}_{2}}OH.$
$RCH=C{{H}_{2}}\xrightarrow[C{{H}_{2}}COOH]{B{{H}_{3}}THF}\underset{\left( A \right)}{\mathop{{{\left( RC{{H}_{2}}C{{H}_{2}} \right)}_{3}}B}}\,\xrightarrow[{}]{{{H}_{2}}{{O}_{2}}/O{{H}^{-}}}\underset{\left( B \right)}{\mathop{RC{{H}_{2}}C{{H}_{2}}OH}}\,$
$\underset{\left( B \right)}{\mathop{RC{{H}_{2}}C{{H}_{2}}OH}}\,\xrightarrow{\underset{\left( D \right)}{\mathop{HI}}\,}\underset{\left( C \right)}{\mathop{RC{{H}_{2}}C{{H}_{3}}}}\,$
Therefore, sequence of reaction A, B, C and D are respectively are $\left[ {{\left( RC{{H}_{2}}C{{H}_{2}} \right)}_{3}}B \right],\left[ RC{{H}_{2}}C{{H}_{2}}OH \right],\left[ RC{{H}_{2}}C{{H}_{3}} \right],\left[ HI \right]$ .

Note :
Remember that the monohydric phenol contains one alcoholic group. The dihydric phenols have two $-OH$ groups. They can be ortho, Meta, and even para-derivative. Finally, the third type of phenols is trihydric phenols, which have three alcoholic groups. When it comes to the classification of ether, students will learn about two types of ether; the first one is symmetrical ether, which is also known as simple ether; in this form of ether, the alkyl or the aryl groups attached to either side of the oxygen atoms are the same.