Question

In the Young’s double slit experiment, the intensity of light passing through each of the two double slits is 2 × 10-2 Wm-2. The screen-slit distance is very large in comparison with slit-slit distance. The fringe width is β. The distance between the central maximum and a point P on the screen is $\frac{\beta}{3}$. Then the total light intensity at that point is

• A. 4 × 10-2 Wm-2
• B. 2 × 10-2 Wm-2
• C. 16 × 10-2 Wm-2
• D. 8 × 10-2 Wm-2

Answer 1

Answer: (B)

2 × 10-2 Wm-2

Answer 2

The correct answer is (B) : 2 × 10-2 Wm-2.