Question

In the Young’s double slit experiment a monochromatic source of wavelength λ is used. The intensity of light passing through each slit is I0. The intensity of light reaching the screen SC at a point P, a distance X from O is given by (Take d << D).

• A. $I_0\ \cos^2(\frac{\pi D}{\lambda d}x)$
• B. $4I_0\ \cos^2(\frac{\pi d}{\lambda D}x)$
• C. $I_0\ \sin^2(\frac{\pi d}{2\lambda D}x)$
• D. $4I_0\ \cos(\frac{\pi d}{2\lambda D}x)$

Answer 1

Answer: (B)

$4I_0\ \cos^2(\frac{\pi d}{\lambda D}x)$

Answer 2

The correct answer is (B) : $4I_0\ \cos^2(\frac{\pi d}{\lambda D}x)$.