Solveeit Logo

Question

Physics Question on Waves

In the wave equation y=05sin2πλ(400tx)my=05 \sin \frac{2 \pi}{\lambda}(400 t-x) m the velocity of the wave will be :

A

200m/s200 m / s

B

2002m/s200 \sqrt{2} m / s

C

400m/s400 m / s

D

4002m/s400 \sqrt{2} m / s

Answer

400m/s400 m / s

Explanation

Solution

From the given options the correct answer is option (C): 400 m/s.