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Question: In the uranium radioactive series, the initial nucleus is \(92U^{238}\)and the final nucleus is\(82P...

In the uranium radioactive series, the initial nucleus is 92U23892U^{238}and the final nucleus is82Pb20682Pb^{206}. When the uranium nucleus decays to lead, the number of α−\alpha -particles emitted will be.

A

1

B

2

C

4

D

8

Answer

8

Explanation

Solution

nα=A−A′4=238−2064=8n_{\alpha} = \frac{A - A'}{4} = \frac{238 - 206}{4} = 8