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Question

Question: In the system shown in the figure, the acceleration of 1kg mass is : <img src="https://cdn.pureesse...

In the system shown in the figure, the acceleration of 1kg mass is :

A

g4\frac { \mathrm { g } } { 4 } downwards

B

g2\frac { \mathrm { g } } { 2 } downwards

C

g2\frac { \mathrm { g } } { 2 } upwards

D

g4\frac { \mathrm { g } } { 4 } upwards

Answer

g2\frac { \mathrm { g } } { 2 } upwards

Explanation

Solution

If a is downward acceleration of 4 kg block, the upward acceleration of 1 kg block must be 2a

Let T be tension in each part of string. The equation of motion on 4 kg block is

4g2T=4a4 g - 2 T = 4 a ….. (i)

The equation of motion or 1 kg block is

T1g=1×2aT - 1 g = 1 \times 2 a …(ii)

Or 2T2g=4a2 T - 2 g = 4 a ….(iii)

Adding (i) and (iii) we get

2g=8a2 g = 8 a or a=g4a = \frac { g } { 4 }

\thereforeAcceleration of 1 kg block

=2a=g2= 2 a = \frac { g } { 2 } upwards.