Question

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is.

• A. 5/27
• B. 1/93
• C. 4/9
• D. 3/2

Answer 1

Answer: (A)

5/27

Answer 2

In Lyman series ${\lambda\frac{4}{3R}}_{\max}$

In Balmer series ${\lambda\frac{36}{5R}}_{\max}$So required ratio $= \frac{5}{27}$.