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Question: In the shown system m<sub>1</sub>\> m<sub>r</sub> . Thread QR is holding the system. If this thread ...

In the shown system m1> mr . Thread QR is holding the system. If this thread is cut, then just after cutting.

A

Acceleration of mass m. is zero and that of m2 is directed upward

B

Acceleration of mass m2 is zero and that of m2 is directed downward.

C

Acceleration of both the blocks will be same.

D

Acceleration of system is given by (m1m2m1+m2)\left( \frac { m _ { 1 } - m _ { 2 } } { m _ { 1 } + m _ { 2 } } \right) kg, where k is a spring factor.

Answer

Acceleration of mass m. is zero and that of m2 is directed upward

Explanation

Solution

On cutting of string QR, the resultant force of m1 remains zero because its weight m1g is balanced by the tension in the spring but on block m2 a resultant upward force (m1 – m2)g is developed. This block m1 will have no resultant whereas m2 does have an upward acceleration given by (m1m2)gm2\frac { \left( m _ { 1 } - m _ { 2 } \right) g } { m _ { 2 } } .