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Question

Question: In the series LCR circuit shown the impedance is <img src="https://cdn.pureessence.tech/canvas_46.p...

In the series LCR circuit shown the impedance is

A

200Ω\Omega

B

100Ω\Omega

C

300Ω\Omega

D

500Ω\Omega

Answer

500Ω\Omega

Explanation

Solution

: Here, , L=1H,C=20μF=20×106FL = 1H,C = 20\mu F = 20 \times 10^{- 6}F

R=300Ω,υ=50πHz.R = 300\Omega,\upsilon = \frac{50}{\pi}Hz.

The inductive reactance is,

XL=2πυL=2×π×50π×1=100ΩX_{L} = 2\pi\upsilon L = 2 \times \pi \times \frac{50}{\pi} \times 1 = 100\Omega

The capacitive reactance is,

XC=12πυC=12×π×50π×20×106=500ΩX_{C} = \frac{1}{2\pi\upsilon C} = \frac{1}{2 \times \pi \times \frac{50}{\pi} \times 20 \times 10^{- 6}} = 500\Omega

The impedance of the series LCR circuit is,

Z=R2+(XCXL)2Z = \sqrt{R^{2} + (X_{C} - X_{L})^{2}}

=(300)2+(500100)2= \sqrt{(300)^{2} + (500 - 100)^{2}}

=(300)2+(400)2=500Ω= \sqrt{(300)^{2} + (400)^{2}} = 500\Omega