Question
Physics Question on Electromagnetic induction
In the series L−C−R circuit shown, the impedance is
A
200Ω
B
100Ω
C
300Ω
D
500Ω
Answer
500Ω
Explanation
Solution
XL=2πfL
=2π(π50)×1=100Ω
XC=2πfC1=2π(π50)20×10−61=500Ω
Impedance, Z=R2+(XC−XL)2
Z=(300)2−(400)2=500Ω