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Question

Physics Question on Electromagnetic induction

In the series LCRL-C-R circuit shown, the impedance is

A

200Ω200 \,\Omega

B

100Ω100 \,\Omega

C

300Ω300\, \Omega

D

500Ω500 \,\Omega

Answer

500Ω500 \,\Omega

Explanation

Solution

XL=2πfLX_{L} =2 \pi f L
=2π(50π)×1=100Ω=2 \pi\left(\frac{50}{\pi}\right) \times 1=100\, \Omega
XC=12πfC=12π(50π)20×106=500ΩX_{C} =\frac{1}{2 \pi f C}=\frac{1}{2 \pi\left(\frac{50}{\pi}\right) 20 \times 10^{-6}}=500\, \Omega
Impedance, Z=R2+(XCXL)2Z =\sqrt{R^{2}+\left(X_{C}-X_{L}\right)^{2}}
Z=(300)2(400)2=500ΩZ =\sqrt{(300)^{2}-(400)^{2}}=500\, \Omega