Question

In the series combination of n cells each cell having emf $\frac{r_{1}r_{2}}{r_{2} - r_{1}}\frac{\rho}{4\pi}$ and internal resistance r. If three cells are wrongly connected, then total emf and internal resistance of this combination will be

• A. $2\Omega,4\Omega$
• B. $5\Omega$
• C. $T_{1}$
• D. $T_{2}$

Answer 1

Answer: (D)

$T_{2}$

Answer 2

: Since due to wrong connection of each cell the total emf reduced to $2\varepsilon$then for wrong connection of three cells the total emf will reduced to $(n\varepsilon - 6\varepsilon)$ whereas the total or equivalent resistance of cell combination will be nr.