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Physics Question on mechanical properties of solids

In the Searle's method to determine the Young's modulus of a wire, a steel wire of length 156 cm and diameter 0.054 cm is taken as experimental wire. The average increase in length for 1121\frac{1}{2} kg wt is found to be 0.05.cm. Then the Young's modulus of the wire

A

3.002×1011N/m23.002 \times 10^{11}N/m^2

B

1.002×1011N/m21.002 \times 10^{11}N/m^2

C

2.002×1011N/m22.002 \times 10^{11}N/m^2

D

2.5×1011N/m22.5 \times 10^{11}N/m^2

Answer

2.002×1011N/m22.002 \times 10^{11}N/m^2

Explanation

Solution

y=FlAey = \frac{Fl}{Ae}