Question

In the reversible reaction, $2NO_2⇋ N_2O_4$ the rate of disappearance of $NO_2$ is equal to

• A. $\frac {2k_1}{k_2}[NO_2]^2$
• B. $2k_1[NO_2]^2-2k_2[N_2O_4]$
• C. $2k_1[NO_2]^2-k_2[N_2O_4]$
• D. $2k_1k_2[NO_2]$

Answer 1

Answer: (B)

$2k_1[NO_2]^2-2k_2[N_2O_4]$

Answer 2

The correct option is (B): $2k_1[NO_2]^2-2k_2[N_2O_4]$.