Question
Question: In the reaction the structure of product T is  Amides are less basic than the respective nitrogen amine, due to the delocalization of lone pairs of the nitrogen.
(ii) N-H bonds in amide are more acidic than amine N-H bonds because the lone pair of conjugate base is more stable due to its resonance delocalization.
(iii) Hoffmann Bromamide reaction:
When an aromatic amide or aliphatic amide is treated with bromine in an aqueous solution of sodium hydroxide, then the degradation of amide takes place leading to the formation of primary amine. This reaction is also known as Hoffmann Bromamide degradation reaction, because in this reaction involves the degradation of amide.
The general equation is,
RCONH2+Br2+4NaOH→R−NH2+Na2CO3+2NaBr+2H2O
The important observation in this reaction is the primary formed as the product is less than one carbon atom of the reactant amide.
If the given compound involves in this reaction:
So, the correct answer is “Option C”.
Note: Except for formamide, is liquid and all simple amides are solids. Like esters, amides solutions in water are neutral, either acidic or basic. Generally, these amides are high boiling points and melting points due to hydrogen bonding in amides and solubility in water more because amide molecules can engage hydrogen bonding with water.