Question
Question: In the reaction <sub>1</sub>H<sup>2</sup> + <sub>1</sub>H<sup>3</sup>¾®<sub>2</sub>He<sup>4</sup> +<...
In the reaction 1H2 + 1H3¾®2He4 +0n1 if the binding energies of 1H2, 1H3 and 2He4 are respectively a, b and c (in MeV), then the energy(in MeV) released in this reaction is-
A
a + b + c
B
a + b – c
C
c – a – b
D
c + a – b
Answer
c – a – b
Explanation
Solution
1H2 + 1H3 ¾® 2He4 + 0n1
a b c
DE = c – (a + b)
DE = c – a – b