Question

In the reaction sequence : $CH_2OH - CHOH - CH_2OH \xrightarrow{KHSO_4/\Delta} (X) \xrightarrow{\frac{(C_2H_5O)_3Al}{\Delta}} (Y). (Y) \text{ will be:}$

• A. Propanal
• B. Propanol
• C. Allyl alcohol
• D. Acrolein

Answer 1

Answer: (C)

Allyl alcohol

Answer 2

The reaction sequence involves two steps:

1. Dehydration: Glycerol ($CH_2OH - CHOH - CH_2OH$) undergoes dehydration in the presence of $KHSO_4$ and heat ($\Delta$) to form acrolein ($CH_2=CH-CHO$).

   $CH_2OH - CHOH - CH_2OH \xrightarrow{KHSO_4/\Delta} CH_2=CH-CHO$

2. Reduction: Acrolein is then reduced by aluminum triethoxide ($(C_2H_5O)_3Al$) to form allyl alcohol ($CH_2=CH-CH_2OH$).

   $CH_2=CH-CHO \xrightarrow{\frac{(C_2H_5O)_3Al}{\Delta}} CH_2=CH-CH_2OH$

Therefore, (Y) is allyl alcohol.