Question

In the reaction: $I_{2} + 2S_{2}O_{3}^{2 -} \rightarrow 2I^{-} + S_{4}O_{6}^{2 -}$

• A. $I_{2}$is reducing agent.
• B. $I_{2}$is oxidizing agent and $S_{2}O_{3}^{2 -}$ is reducing agent.
• C. $S_{2}O_{3}^{2 -}$is oxidizing agent.
• D. $I_{2}$ is reducting agent and $S_{2}O_{3}^{2 -}$ is oxidizing agent.

Answer 1

Answer: (B)

$I_{2}$is oxidizing agent and $S_{2}O_{3}^{2 -}$ is reducing agent.

Answer 2

: $\overset{0}{12} \rightarrow \overset{- 1}{2I^{-}}$

$I_{2}$ Undergoes reduction hence acts as oxidising gent.

$S_{2}^{+ 2}O_{3}^{2 -} \rightarrow S_{4}^{+ 2.5}O_{6}^{2 -}$

It undergoes oxidation hence acts as a reducing agent.