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Question: In the reaction \(C_{2}O_{4}^{2 -} + MnO_{4}^{-} + H^{+} \rightarrow Mn^{2 +} + CO_{2} + H_{2}O\) t...

In the reaction C2O42−+MnO4−+H+→Mn2++CO2+H2OC_{2}O_{4}^{2 -} + MnO_{4}^{-} + H^{+} \rightarrow Mn^{2 +} + CO_{2} + H_{2}O

the reductant is.

A

C2O42−C_{2}O_{4}^{2 -}

B

MnO4−MnO_{4}^{-}

C

Mn2+Mn^{2 +}

D

H+H^{+}

Answer

C2O42−C_{2}O_{4}^{2 -}

Explanation

Solution

C2O42−+MnO4−+H+→Mn2++CO2+H2OC_{2}O_{4}^{2 -} + MnO_{4}^{-} + H^{+} \rightarrow Mn^{2 +} + CO_{2} + H_{2}O.

In this reaction C2O42−C_{2}O_{4}^{2 -} act as a reducing agent.