Question

In the reaction $A(s)+B(g)+$ heat $\rightleftharpoons 2C(s)+2D(g)$ at equilibrium, pressure of $B$ is doubled to re-establish the equilibrium. The factor by which concentration of $D$ is changed, is:

• A. $\sqrt{2}$
• B. $2$
• C. $3$
• D. $2\sqrt{2}$

Answer 1

Answer: (A)

$\sqrt{2}$

Answer 2

For reaction, $K_{p}=\frac{[D]^{2}}{[B]}$ Hence, for this reaction, $\frac{\left[D_{1}\right]^{2}}{\left[B_{1}\right]}=\frac{\left[D_{2}\right]^{2}}{\left[2 B_{1}\right]}$ or $\left[D_{2}\right]=\sqrt{2}\left[D_{1}\right]$