Solveeit Logo
Login

Question

Question: In the reaction A + 2B \(\longrightarrow\) 3C + D....

In the reaction A + 2B ⟶\longrightarrow 3C + D.

A

d[C]dt\frac{d\lbrack C\rbrack}{dt} = – 3d[A]dt\frac{3d\lbrack A\rbrack}{dt}

B

3d[C]dt\frac{3d\lbrack C\rbrack}{dt} = – 2d[B]dt\frac{2d\lbrack B\rbrack}{dt}

C

–d[B]2dt\frac{–d\lbrack B\rbrack}{2dt} = +d[B]3dt\frac{+ d\lbrack B\rbrack}{3dt}

D

None of these

Answer

–d[B]2dt\frac{–d\lbrack B\rbrack}{2dt} = +d[B]3dt\frac{+ d\lbrack B\rbrack}{3dt}

Explanation

Solution

= RC3\frac{R_{C}}{3}