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Question: In the reaction \(2N_{2}O_{5} \rightarrow 4NO_{2} + O_{2}\), initial pressure is \(500atm\) and rate...

In the reaction 2N2O5→4NO2+O22N_{2}O_{5} \rightarrow 4NO_{2} + O_{2}, initial pressure is 500atm500atm and rate constant KK is 3.38×10−5sec⁡−13.38 \times 10^{- 5}\sec^{- 1}{}. After 10 minutes the final pressure of N2O5N_{2}O_{5} is.

A

490 atm

B

250 atm

C

480 atm

D

420 atm

Answer

490 atm

Explanation

Solution

p0=500atmp_{0} = 500atm

K=2.303tlog⁡10p0ptK = \frac{2.303}{t}\log_{10}\frac{p_{0}}{p_{t}}

3.38×10−5=2.30310×60log⁡500pt3.38 \times 10^{- 5} = \frac{2.303}{10 \times 60}\log\frac{500}{p_{t}}

or 0.00880=log⁡500pt⇒5001.02=490atm0.00880 = \log\frac{500}{p_{t}} \Rightarrow \frac{500}{1.02} = 490atm