Question
Chemistry Question on Rate of a Chemical Reaction
In the reaction 2A+B→A2B, if the concentration of A is doubled and that of B is halved, then the rate of reaction will
A
increase by 4 times
B
decrease by 2 times
C
increase by 2 times
D
remains the same
Answer
increase by 2 times
Explanation
Solution
For the reaction: 2A+B→A2Br=k[A]2[B]
If concentration of A is doubled and that of B is halved, then
r′=[2A]2[2B]
2k[A]2[B]r′=2r
Hence, if the concentration of
[A] is doubled and
[B] is halved, then rate of reaction increases by 2 times.