Solveeit Logo

Question

Chemistry Question on Rate of a Chemical Reaction

In the reaction 2A+BA2B2 A+B \rightarrow A_{2} B, if the concentration of AA is doubled and that of BB is halved, then the rate of reaction will

A

increase by 4 times

B

decrease by 2 times

C

increase by 2 times

D

remains the same

Answer

increase by 2 times

Explanation

Solution

For the reaction: 2A+BA2Br=k[A]2[B]2 A+B \rightarrow A_{2} B r=k[A]^{2}[B]
If concentration of AA is doubled and that of BB is halved, then
r=[2A]2[B2]r'=[2 A]^{2}\left[\frac{B}{2}\right]
2k[A]2[B]r=2r2 k[A]^{2}[B] r'=2 r
Hence, if the concentration of
[A] is doubled and
[B] is halved, then rate of reaction increases by 2 times.