Question
Question: In the pulley system shown in the figure, if radii of bigger and smaller pulley are \(2\;{\rm{m}}\) ...
In the pulley system shown in the figure, if radii of bigger and smaller pulley are 2m and 1m respectively and acceleration of block A is 5m/s2in the downward direction, then the acceleration of block B will be,
A. 0m/s2
B. 5m/s2
C. 10m/s2
D. 5/2m/s2
Solution
In the solution we will use the relation between the linear acceleration and angular acceleration. Also, there is no need to draw a free body diagram and calculate the force acting on both the blocks. We will also use the concept of a rotating body about a fixed axis in which each particle has the same angular velocity and angular acceleration.
Complete step by step answer:
Given:
The radius of the smaller pulley is, r=1m.
The radius of the bigger pulley is,R=2m
The acceleration of block A is,aA=5m/s2
The relation between linear and angular acceleration is,
a=αr
Angular acceleration of block A is,
αA=RaA … (i)
Angular acceleration of block B is,
αB=raB … (ii)
As both the pulleys are pivoted at the same point and connected to each other, thus both the pulleys have the same angular velocity and angular acceleration.
αA=αB ⇒RaA=raB
Rearranging the above terms,
aB=RaAr
Substitute the necessary values and calculate the linear acceleration of block B,
aB=2m(5m/s2)⋅(1m) ∴aB=25m/s2
Thus, the acceleration of block B is 25m/s2. Hence option D is the correct answer.
Note: Make sure to use the concept of rotational motion that both the pulleys have the same acceleration to get the appropriate result and also remember that the linear acceleration of both the blocks are depend upon the distance of block from the pivoted point thus block A have more linear acceleration than block B.