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Question: In the preceeding problem, if [A+] and [AB2] are y and x respectively, under equilibrium produced b...

In the preceeding problem, if [A+] and [AB2] are y and x respectively, under equilibrium produced by adding the substance AB to the solvents, then K1/K2 is equal to

A

yx(y−x)2\frac { y } { x } ( y - x ) ^ { 2 }

B

y2(x+y)x\frac { y ^ { 2 } ( x + y ) } { x }

C

y2(x+y)x\frac { y ^ { 2 } ( x + y ) } { x }

D

yx(x−y)\frac { y } { x } ( x - y )

Answer

yx(y−x)2\frac { y } { x } ( y - x ) ^ { 2 }

Explanation

Solution

⇌\rightleftharpoons A++B−AB+B−\mathrm { A } ^ { + } + \mathrm { B } ^ { - } \quad \mathrm { AB } + \mathrm { B } ^ { - } ⇌\rightleftharpoons

a–x–y y (y–x) (a–x–y) y–x xK1=y(y−x)(a−x−y)K _ { 1 } = \frac { y ( y - x ) } { ( a - x - y ) }