Question

In the plot of log $\frac{x}{m}$ $vs \, log \, p$ for an adsorption, a straight line inclined at an angle of $\theta=14.04^{\circ}$ to the $x$-axis was obtained. The $'n'$ value for this adsorption process is $( tan \, 14.04^{\circ}=0.25)$

• A. $5$
• B. $8$
• C. $4$
• D. $2$

Answer 1

Answer: (C)

$4$

Answer 2

Plot of log $\frac{x}{m}vs$ log $p$ is a straight line with
slope $=\frac{1}{n}$
Also, slope $=tan\, \theta=tan\, 14.04^{\circ}=0.25$
$\Rightarrow \frac{1}{n}=0.25$
or $n=4$