Question

In the nuclear reaction$92U^{238} \rightarrow_{z}Th^{A} +_{2}He^{4}$, the values of A and Z are.

• A. A = 234, Z = 94
• B. A = 234, Z = 90
• C. A = 238, Z = 94
• D. A = 238, Z = 90

Answer 1

Answer: (B)

A = 234, Z = 90

Answer 2

A = 238 – 4 = 234 and Z = 92 – 2 = 90.