Question

In the nuclear reaction: $X(n,\alpha)_{3}Li^{7}$ the term X will be 3

• A. $5B^{10}$
• B. $5B^{9}$
• C. $5B^{11}$
• D. $2He^{4}$

Answer 1

Answer: (A)

$5B^{10}$

Answer 2

$X(n,\mspace{6mu}\alpha)\mspace{6mu}_{3}^{7}Li \Rightarrow_{Z}X^{A} +_{0}n^{1} \rightarrow 3Li^{7} +_{2}He^{4}$

$Z = 3 + 2 = 5$and A= 7+4 – 1 =10

$\therefore_{5}X^{10} =_{5}B^{10}$