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Question: In the nuclear reaction, <sub>1</sub>H<sup>2</sup> + <sub>1</sub>H<sup>2</sup>®<sub>0</sub>n<sup>1<...

In the nuclear reaction,

1H2 + 1H2®0n1 + 2He3

if the binding energy of deuteron is 2.23 MeV and the Q-value of the reaction is 3.27 MeV then the binding energy of 2He3 is-

A

1.19 MeV

B

7.73 MeV

C

4.46 MeV

D

3.27 MeV

Answer

7.73 MeV

Explanation

Solution

1H2 + 1H2 ® 0n1 + 2He3 + D E

2.23 MeV 2.23 MeV E f

D E = 3.27 MeV = E f – (2.23 + 2.23)

E f = 3.27 + 4.46 = 7.73 MeV