Question
Question: In the nuclear reaction, <sub>1</sub>H<sup>2</sup> + <sub>1</sub>H<sup>2</sup>®<sub>0</sub>n<sup>1<...
In the nuclear reaction,
1H2 + 1H2®0n1 + 2He3
if the binding energy of deuteron is 2.23 MeV and the Q-value of the reaction is 3.27 MeV then the binding energy of 2He3 is-
A
1.19 MeV
B
7.73 MeV
C
4.46 MeV
D
3.27 MeV
Answer
7.73 MeV
Explanation
Solution
1H2 + 1H2 ® 0n1 + 2He3 + D E
2.23 MeV 2.23 MeV E f
D E = 3.27 MeV = E f – (2.23 + 2.23)
E f = 3.27 + 4.46 = 7.73 MeV