In the Nuclear reaction given below : (\_7N^{14}+2He^4\right... | Physics | SolveeIt | Solveeit

Today, August 20

Question

In the Nuclear reaction given below : $_7N^{14}+2He^4\rightarrow\,X+_1H^1$ , the nucleus X is

A

$_8N^{17}$

B

$_8N^{16}$

C

$_8O^{17}$

D

$_8O^{16}$

Answer

$_8O^{17}$

Explanation

Solution

$_8O^{17}$