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Question: In the nuclear reaction \(6C^{11} \rightarrow_{5}B^{11} + \beta^{+} + X\), what does X stand for....

In the nuclear reaction 6C11→5B11+β++X6C^{11} \rightarrow_{5}B^{11} + \beta^{+} + X, what does X stand for.

A

An electron

B

A proton

C

A neutron

D

A neutrino

Answer

A neutrino

Explanation

Solution

6C11→5B11+β++γ6C^{11} \rightarrow_{5}B^{11} + \beta^{+} + \gammabecause β+=1e0\beta^{+} =_{1}e^{0}