Question

In the magnetic meridian of a certain place the horizontal component of earth?? magnetic field is 0.25 G and dip angle is $60^?$. The magnetic field of the earth at this location is

• A. 0.50 G
• B. 0.52 G
• C. 0.54 G
• D. 0.56 G

Answer 1

Answer: (A)

0.50 G

Answer 2

Here, $H_E = 0.25\, G$ and $cos\,?$ $=\frac{H_{E}}{B_{E}}$ $\therefore$ The magnetic field of earth at the given location is $B_{E}=\frac{H_{E}}{cos\,60^{?}}=\frac{0.25}{1 / 2}=0.50\,G$