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Question: In the M K S system, Stefan’s constant is denoted by \[\sigma \] . In C G S system multiplying facto...

In the M K S system, Stefan’s constant is denoted by σ\sigma . In C G S system multiplying factor of σ\sigma will be
A. 11
B. 103{10^3}
C. 105{10^5}
D. 102{10^2}

Explanation

Solution

The Stefan Boltzmann constant also called Stefan’s constant is the total intensity radiated over all wavelengths increases as the temperature increases of a black body which is proportional to the fourth power of the thermodynamic temperature. In this problem the M K S unit of the Stephan’s constant should be converted to a C G S unit.

Complete step by step answer:
Stephan’s constant is given by, EnergyArea×time×temperature\dfrac{{Energy}}{{Area \times time \times temperature}} . …………. (1)\left( 1 \right)
In M K S system, the unit of Stephan constant (σ)\left( \sigma \right) is Jm2×sec×K4\dfrac{J}{{{m^2} \times \sec \times {K^4}}} ……….. (2)\left( 2 \right)
On converting S I unit to C G S unit is
We know that,
1 joule = 107{10^7} erg.
1m2=104cm21\,{m^2} = {10^4}c{m^2} .
On substituting in equation (2)\left( 2 \right)
We get, the C G S unit of Stephan constant as,
107erg104cm2×sec×K4\dfrac{{{{10}^7}erg}}{{{{10}^4}c{m^2} \times \sec \times {K^4}}}
On simplifying the above equation, we get
1074ergcm2×sec×K4\dfrac{{{{10}^{7 - 4}}erg}}{{c{m^2} \times \sec \times {K^4}}}
103ergcm2×sec×K4\Rightarrow \dfrac{{{{10}^3}erg}}{{c{m^2} \times \sec \times {K^4}}}
Therefore, the multiplying factor of Stephen factor σ\sigma in C G S is 103{10^3}.

Hence, the correct option is B.

Additional information: Dimensional formula for Stefan Boltzmann constant is
On using equation (1)\left( 1 \right)
Stefan constant = [ML2T2][L2][T][K4]\dfrac{{\left[ {M{L^2}{T^{ - 2}}} \right]}}{{\left[ {{L^2}} \right]\left[ T \right]\left[ {{K^4}} \right]}}
Therefore, Stefan's constant dimensional formula = [ML0T3K4]\left[ {M{L^0}{T^{ - 3}}{K^{ - 4}}} \right].
Some of the applications of Stefan Boltzmann constant are:
-Stefan Boltzmann constant is used to measure the amount of heat that is radiated from the black body.
-Stefan Boltzmann constant is used to convert temperature (K)\left( K \right) to units for intensity (Wm2)\left( {W{m^{ - 2}}} \right) that is basically power per unit area.

Note: It should be noted that the unit for time is same in both M K S and C G S unit that is seconds and also unit for temperature is same in both M K S and C G S unit that is Kelvin and the value of Boltzmann constant is 8.617×105eVK18.617 \times {10^{ - 5}}eV{K^{ - 1}}.