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Question: In the loop shown, the magnetic induction at the point 'O' is A. \(\dfrac{{{\mu _0}I}}{8}\left(...

In the loop shown, the magnetic induction at the point 'O' is

A. μ0I8(R1R2R1R2)\dfrac{{{\mu _0}I}}{8}\left( {\dfrac{{{R_1} - {R_2}}}{{{R_1}{R_2}}}} \right)
B. μ0I8(R1+R2R1R2)\dfrac{{{\mu _0}I}}{8}\left( {\dfrac{{{R_1} + {R_2}}}{{{R_1}{R_2}}}} \right)
C. μ0I8(R1R2R1+R2)\dfrac{{{\mu _0}I}}{8}\left( {\dfrac{{{R_1}{R_2}}}{{{R_1} + {R_2}}}} \right)
D. Zero

Explanation

Solution

Hint: In this question we will place the Biot-Savart law. Through which we can conclude that the magnetic field along the line of a straight current carrying conductor is zero. Then we need to know the magnetic fields due to sections AB, CD, EF & FG are zero at point O. Then by placing the formula of Magnetic field at the center of a current carrying loop we can find our basic answer.

Complete step-by-step answer:

The magnetic field in the lines of a straight current conveying conductor may be concluded with Biot-Savart 's rule to be zero.
Hence, magnetic fields due to sections AB, CD, EF & FG are zero at point O.
Magnetic field at the center of a current carrying loop is represented by:
B=μ0I2R\Rightarrow B = \dfrac{{{\mu _0}I}}{{2R}}
Now, the magnetic field due to the section BC would be
BBC=14×μ0I2R\Rightarrow {B_{BC}} = \dfrac{1}{4} \times \dfrac{{{\mu _0}I}}{{2R}} Inside the plane of paper (by using right hand thumb rule)
We can see that the factor 14\dfrac{1}{4} appears as only one fourth of the total circumference contributes to the magnetic field.
Now similarly, magnetic field due to section DE would be
BDE=μ0I8R\Rightarrow {B_{DE}} = \dfrac{{{\mu _0}I}}{{8R}}Which is inside the plane of paper (by using right hand thumb rule)
Now the total magnetic field at point O is
B=BAB+BBC+BCD+BDE+BEF+BFG\Rightarrow B = {B_{AB}} + {B_{BC}} + {B_{CD}} + {B_{DE}} + {B_{EF}} + {B_{FG}}
B=μ0I8R1+μ0I8R2\Rightarrow B = \dfrac{{{\mu _0}I}}{{8{R_1}}} + \dfrac{{{\mu _0}I}}{{8{R_2}}} Inside the plane of paper
B=μ0I8(R1+R2R1R2)\Rightarrow B = \dfrac{{{\mu _0}I}}{8}\left( {\dfrac{{{R_1} + {R_2}}}{{{R_1}{R_2}}}} \right)
Hence, the magnetic induction at the point 'O' is calculated to be-
B=μ0I8(R1+R2R1R2)\Rightarrow B = \dfrac{{{\mu _0}I}}{8}\left( {\dfrac{{{R_1} + {R_2}}}{{{R_1}{R_2}}}} \right)
Thus, option B will be the correct option.

Note- The development of an electromotive (i.e. voltage) force by an electrical conductor in a shifting magnetic field is electromagnetic or magnetic induction. The theory of induction by Michael Faraday in 1831 was widely attributed and James Clerk Maxwell mathematically represented it as the rule of induction by Faraday.