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Question

Chemistry Question on Electrochemistry

In the lead-acid battery during charging, the cathode reaction is

A

formation of PbO2PbO_2

B

formation of PbSO4PbSO_{4}

C

reduction of Pb2+Pb^{2+} to PbPb

D

decomposition of PbPb at the anode

Answer

formation of PbO2PbO_2

Explanation

Solution

The cell reactions during charging of lead storage battery are
PbSO4(s)+2e>Pb(s)+SO42(aq)PbSO_4(s) + 2e^- {->} Pb(s) + SO_4^{2-} (aq)
PbSO4(s)+2H2O>PbO2(s)+SO42(aq)4H++2ePbSO_4 (s) + 2H_2O {->} PbO_2(s) + SO_4^{2-} (aq) - 4H^+ +2e^-
Thus, at cathode, formation of PbO2PbO_2 takes place.