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Question

Chemistry Question on Redox reactions

In the ionic equation : BiO3+6H++XeBi3++3H2OBiO _{3}^{-}+6 H ^{+}+ Xe ^{-} \longrightarrow Bi ^{3+}+3 H _{2} O the value of XX is -

A

3

B

4

C

2

D

6

Answer

2

Explanation

Solution

The correct answer is C:2
BiO3+6H++xe>Bi3++3H2O{BiO3^{-} + 6H^{+} + xe^{-} -> Bi^{3+} + 3H2O}
By electron neutrality principle,
1+6+x(1)=3+0-1 + 6 + x (-1) = 3 + 0
+5+x(1)=3\Rightarrow +5 + x(-1) = 3
x=+2\Rightarrow x = +2