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Question

Mathematics Question on Binary operations

In the group G=1,5,7,11G = \\{1,5,7,11\\} under multiplication modulo 1212, the solution of 71  12(x1211)=5 7^{-1} \; \otimes_{12} (x \otimes_{12} 11) = 5 is xx =

A

11

B

7

C

1

D

5

Answer

1

Explanation

Solution

Given that
G=1,5,7,11G=\\{1,5,7,11\\} is a group under multiplication modulo 12
71=7\therefore 7^{-1}=7
(71127=1)\left(\because 7^{-1} \otimes_{12} 7=1\right)
Now, 7112(x1211)=57^{-1} \otimes_{12}\left(x \otimes_{12} 11\right)=5
712(1112x)=5\Rightarrow 7 \otimes_{12}\left(11 \otimes_{12} x\right)=5
(71211)12x=5\Rightarrow \left(7 \otimes_{12} 11\right) \otimes_{12} x=5
512x=5\Rightarrow 5 \otimes_{12} x=5
x=1\Rightarrow x=1