Question
Mathematics Question on Binary operations
In the group G=1,5,7,11 under multiplication modulo 12, the solution of 7−1⊗12(x⊗1211)=5 is x =
A
11
B
7
C
1
D
5
Answer
1
Explanation
Solution
Given that
G=1,5,7,11 is a group under multiplication modulo 12
∴7−1=7
(∵7−1⊗127=1)
Now, 7−1⊗12(x⊗1211)=5
⇒7⊗12(11⊗12x)=5
⇒(7⊗1211)⊗12x=5
⇒5⊗12x=5
⇒x=1