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Question

Mathematics Question on Binary operations

In the group G.=1,3,7,9G. = \\{1, 3,7,9 \\} under multiplication modulo 1010, the inverse of 33 is

A

1

B

3

C

7

D

9

Answer

7

Explanation

Solution

Given, G=1,3,7,9G=\\{1,3,7,9\\}
Here, 1×101=1,3×101=3,7×101=71 \times{ }_{10} 1=1,3 \times{ }_{10} 1=3,7 \times{ }_{10} 1=7
9×101=99 \times_{10} 1=9
It is clear that 1 is the identity element. Since, GG is a group, then inverse of each element exist in GG.
3×107=1=7×103\Rightarrow 3 \times_{10} 7=1=7 \times_{10} 3
7G\therefore \,7 \in G is the inverse of 3