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Question

Mathematics Question on Relations and functions

In the group G=0,1,2,3,4,5G= \\{0, 1,2, 3,4, 5\\} under addition modulo 6,(2+63−1+64)−16,(2 +_6 3^{-1} +_6 4)^{-1}=

A

0

B

2

C

3

D

5

Answer

3

Explanation

Solution

(2+63−1+64)−1=(2+63+64)−1     (∵3−1=3)\left(2+{ }_{6} 3^{-1}+{ }_{6} 4\right)^{-1}=\left(2+{ }_{6} 3+{ }_{6} 4\right)^{-1} \,\,\,\,\,\left(\because 3^{-1}=3\right) =(5+64)−1=(3)−1=(5+64)^{-1}=(3)^{-1} =3=3