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Question: In the given, the current drawn from the source is ![](https://www.vedantu.com/question-sets/...

In the given, the current drawn from the source is

A.20A20A
B.10A10A
C.5A5A
D.52A5\sqrt{2}A

Explanation

Solution

In this question, we find out the total current drawn from the source. We divide this circuit into three parts and find the current in the resistor first then find the current in the inductor and then the current in the capacitor. After that, we find the total current in the circuit.
According to the equation v=v0sin(ωt)v={{v}_{0}}\sin (\omega t)we get, the value of the V0{{V}_{0}} and ω\omega by comparing the given equation.
So, V0=100V{{V}_{0}}=100\,V
ω=100π\omega =100\,\pi
We are going to use a basic formula for an electrical circuit.

Complete answer:
All the three are connected in parallel so the voltage is the same across them
Given that
XL=10Ω{{X}_{L}}=10\,\Omega
XC=20Ω{{X}_{C}}=20\,\Omega
R=20ΩR=20\,\Omega
V=100V{{V}_{\circ }}=100\,V
Current in resistor iR=V0R{{i}_{R}}=\dfrac{{{V}_{0}}}{R}
Current in the inductor iL=V0XL{{i}_{L}}=\dfrac{{{V}_{0}}}{{{X}_{L}}}
Current in capacitor iC=V0XC{{i}_{C}}=\dfrac{{{V}_{0}}}{{{X}_{C}}}
iR=V0R{{i}_{R}}=\dfrac{{{V}_{0}}}{R}
Now we substitute the given values in the equation
10020=5amp.\Rightarrow \dfrac{100}{20}=5\,amp.
Now calculate current in the inductor
iL=V0XL{{i}_{L}}=\dfrac{{{V}_{0}}}{{{X}_{L}}}
Now we substitute the given values in the equation
10010=10amp.\Rightarrow \dfrac{100}{10}=10\,amp.
Now the current in the capacitor is
iC=V0XC{{i}_{C}}=\dfrac{{{V}_{0}}}{{{X}_{C}}}
After substituting the given values we get,
10020=5amp.\Rightarrow \dfrac{100}{20}=5\,amp.
So, the total current I=(iR)+(iL+iL)jI=({{i}_{R}})+({{i}_{L}}+{{i}_{L}})j
Therefore magnitude of the current ii
Current, i=iR2+(iCiL)2i=\sqrt{i_{R}^{2}+{{({{i}_{C}}-{{i}_{L}})}^{2}}}
=52+52=52amp=\sqrt{{{5}^{2}}+{{5}^{2}}}=5\sqrt{2}\,amp.
So the total current is drawn from the source is 52amp.5\sqrt{2}\,amp.

Note:
To solve this type of question we know the basics of electrical circuits. And their formulas to solve the circuits. We can use the different methods to solve the circuits like the nodal method and Thevenin's theorem and the other methods. To know about these methods we have to learn about circuit analysis. After studying these methods, you can easily solve these types of questions.