Question

In the given structure of a compound, the correct various bond moments direction involving are shown as

• A. $Br\underline{\leftarrow }N\underline{\leftarrow }CH_{2}\underline{\to }SiH_{2}\underline{\leftarrow }CH_{2}\underline{\to }O\underline{\leftarrow }CH_{3}$
• B. $Br\underline{\leftarrow }N\underline{\leftarrow }CH_{2}\underline{\leftarrow }SiH_{2}\underline{\leftarrow }CH_{2}\underline{\to }O\underline{\leftarrow }CH_{3}$
• C. $Br\underline{\leftarrow }N\underline{\to }CH_{2}\underline{\leftarrow }SiH_{2}\to CH_{2}\underline{\to }O\underline{\leftarrow }CH_{3}$
• D. $Br\underline{\leftarrow }N\underline{\to }CH_{2}\underline{\to }SiH_{2}\underline{\leftarrow }CH_{2}\underline{\to }O\underline{\to }CH_{3}$

Answer 1

Answer: (C)

$Br\underline{\leftarrow }N\underline{\to }CH_{2}\underline{\leftarrow }SiH_{2}\to CH_{2}\underline{\to }O\underline{\leftarrow }CH_{3}$

Answer 2

Bond moments in a compound is shown by electron pushing arrows. It is the movement of electrons from an electron rich site (a lone pair of electrons or a bond) to an electron poor site and it is generally shown from less electronegative to more electronegative atom.