Question

In the given relation P = $\frac{b - x^{2}}{at}$, where P is power, x is distance and t is time, the dimensions of 'a' will be –

• A. [M^–1 L⁰ T^–2]
• B. [M^–1 L⁰ T²]
• C. [M⁰L²T⁰]
• D. [MLT^–1]

Answer 1

Answer: (B)

$M^–1 L⁰ T²$

Answer 2

a = $\frac{\lbrack L^{2}\rbrack}{\lbrack ML^{2}T^{- 2}\rbrack}$ = [M^–1L⁰T²]