Question

In the given reaction $C{H_2} = C{H_2}\xrightarrow[{Bayers}]{{reagent}}(X)$.find the correct option
A. common name of X is ethylene glycol
B. X is a trihydric alcohol
C. X is used as an antifreeze
D. $S{P^3}$, $S{P^2}$carbons are present in X

Answer 1

Bayer’s reagent used in this reaction is alkaline solution of potassium permanganate which is an oxidizing agent which oxidises ethene which is an unsaturated compound in a saturated alcohol containing two hydroxyl group.

Complete step by step answer:
Baeyer's reagent is commonly an alkaline solution of potassium permanganate which is violet in color. The alkaline solution of potassium permanganate is used as a strong oxidizing agent used to carry out an oxidation reaction.
On reacting with a compound carrying double bond the violet color of the solution disappears and changes to colorless.
The alkaline solution of potassium permanganate on reacting with alkene undergoes oxidation reaction to form ethylene glycol.
The reaction is shown below.
$C{H_2} = C{H_2}\xrightarrow[{Bayers}]{{reagent}}{(C{H_2}OH)_2}$
In this reaction ethene reacts with Baeyer's reagent to form ethylene glycols. The IUPAC name of ethylene glycol is ethane-1,2-diol.
The trihydric alcohols are defined as those alcohols which contain three hydroxyl groups in the compound. Example: glycol. In ethylene glycol only two hydroxyl groups are attached to two carbon atoms. Therefore, ethylene glycol is not a trihydric alcohol.
The ethylene glycol is used as an antifreeze and coolant which is used to prevent the car engine from freezing in winter.
In ethylene glycol $s{p^3}$ and $s{p^2}$ carbon is not present.

So, the correct answer is Option A,C.

Note: In the oxidation of ethene or ethylene with the help of potassium permanganate results in the formation of intermediate ethylene oxide with further on reaction with water from ethylene glycol.