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Question

Chemistry Question on Equilibrium

In the given reaction : A+2B2CA + 2B \rightleftharpoons 2C moles each of A and B present in 10 L of solution combine to form 1 mole of C. Calculate KcK_c for the reaction.

A

1.5

B

6.67

C

0.15

D

2.3

Answer

6.67

Explanation

Solution

A+2B?2C Initiallymole220 Atequilibrium2x22x2x =1.5=1=1\begin{matrix}&A&+&2B&?&2C\\\ Initially mole&2&&2&&0\\\ At equilibrium&2-x&&2-2x&&2x\\\ &=1.5&&=1&&=1\end{matrix} As 1 mole of C is formed at equilibrium, \quad\quad2x = 1 ?? x = 0.5 ?? \quadEquilibrium concentration of A = 1.5/10 \quad\quadB = 1/10 and C = 1/10 Kc=[C]2[A][B]2=[1/10]2[1.5/10][1/10]2=6.67K_{c}=\frac{\left[C\right]^{2}}{\left[A\right]\left[B\right]^{2}}=\frac{\left[1/10\right]^{2}}{\left[1.5 / 10\right]\left[1 / 10\right]^{2}}=6.67