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Question

Question: In the given question, \(\sin 0^\circ \times \sin 1^\circ .............sin90^\circ = \) A. \(0\...

In the given question, sin0×sin1.............sin90=\sin 0^\circ \times \sin 1^\circ .............sin90^\circ =

A. 00
B. tan0\tan 0^\circ
C. sec90\sec 90^\circ
D. cos90\cos 90^\circ

Explanation

Solution

Hint – We will note down the question and then we will draw a Trigonometric Ratios Table to find some values. Then we will put the values in the given question and after multiplying them we will get our required answer.

Complete step-by-step answer:

Given, question is,
sin0×sin1×.............×sin90\sin 0^\circ \times \sin 1^\circ \times ............. \times \sin 90^\circ ………… (1)

Now, using a trick we will make a Trigonometric Ratios Table, with the help of which we will find the values of the ratios given in the Question.

Look at your left hand, suppose the fingers denote the angles. The thumb denotes 00^\circ , the index finger denotes 3030^\circ , the middle finger denotes 4545^\circ , the ring finger denotes 6060^\circ and the little finger denotes 9090^\circ .Let's find out the values if sine. In this method, for sine, count the number of fingers towards the left. Then divide the number by 4 and take the square root of this ratio. For example, for sin0\sin 0^\circ , count the number of fingers to the left of the thumb, which is 0. Then divide 0 with four, which is 0. Therefore, sin0\sin 0^\circ =0.
Now, we can find other values by using this trick.


Now, by using this table equation (1) becomes,
0×sin1×..........×1 =0  0 \times \sin 1^\circ \times .......... \times 1 \\\ = 0 \\\
Hence, option A is the right answer.

Note – Trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths. For solving this question, the different values of the trigonometric ratios must be remembered, for convenience you can draw the table using the trick mentioned above.