Question

In the given nuclear reaction, how many α and β particles are emitted $92X^{235} \rightarrow \mspace{6mu}_{82} ⥂ Y^{207}$

• A. 3α particles and 2β particle
• B. 4α particles and 3β particle
• C. 6α particles and 4β particle
• D. 7α particles and 4β particle

Answer 1

Answer: (D)

7α particles and 4β particle

Answer 2

$n_{\alpha} = \frac{A - A'}{4} = \frac{235 - 207}{4} = 7$

$n_{\beta} = (2n_{\alpha} - Z + Z') = (2 \times 7 - 92 + 82) = 4$